Thursday, May 1, 2014

Example of Bombelli's Algebra

Bombelli frequently used fractions to approximate square roots.  Here is an example:

Suppose we want to find the square root of 13.  The nearest square is 9, which has root 3.  The approximation of the square root of thirteen is 3 + an unknown.

3 + x = √13

Its square is 9 plus 6 unknowns plus 1 power.  We set this equal to 13

(3 + x)2 = 9 + 6x + x2 = 13

Subtract 9 from either side of the equation, and we are left with 4 equal to 6 plus 1 power

6x + x2 = 4

If you ignore the power and set 6 unknowns equal to 4, the unknown (x) equals 2/3

6x = 4 gives x = 2/3

The approximate value of the root is 3 2/3 since it has been set equal to 3 plus 1 unknown.

√13 = 3 + x = 3 2/3

However, taking the power into account, if the unknown equals 2/3 , the power will be  2/3 of an unknown which, added to the 6 unknowns, will give us 6 and  2/3 unknowns.  This equals 4.

6x + x2 = 4 implies 6x + 2/3 x = 4

The unknown will be equal to 3/5  and since the approximate is 3 plus 1 unknown, it comes to 3 3/5.

x = 4/(6 + 2/3) = implies 3 + x = 3 3/5

But if the unknown equals 3/5 the power will be 3/5 of an unknown and we obtain 6 3/5 unknowns equal to 4

6x + x2 = 4 implies 6x + 3/5 x = 4

Then the unknown comes out to be 20/33

6x + 3/5 x = 4 implies x = 4/(6 + 3/5) = 20/33

And this process can continue.

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